Differentiate the following function w.r.t. x:
xsin x + (sin x)cos x .
Let,
y = xsin x + (sin x)cos x
Let, u = xsin x
v = (sin x)cos x
y = u + v
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Now,
u = xsin x
Taking log both sides,
log u = log (xsin x)
⇒ log u = (sin x)(log x)
Differentiating both sides, we get
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v = (sin x)cos x
Taking log both sides,
log v = log((sin x)cos x)
⇒ log v = (cos x) (log (sin x))
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