Q1 of 76 Page 10

In Fig. 10.92, it is given that AB = CD and AD = BC. Prove that Δ ADC ≅ Δ CBA.

Given, in the figure


AB = CD


And,


AD = BC


To prove: Δ ADC ≅ Δ CBA


Proof: Consider,


AB = CD (Given)


BC = AD (Given)


AC = AC (Common)


By SSS theorem,


Δ ADC ≅ Δ CBA


Hence, proved


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