Q17 of 76 Page 11

In Fig. 10.139, ABC is an isosceles triangle whose side AC is produced to E. Through C, CD is drawn parallel to BA. The value of x is

∠B = ∠C (Angles opposite to equal sides are equal)

In ABC,


∠A + ∠B+ ∠C= 180°


∠A = 76°


Now,


∠BAC= ∠ACD (Alternate angles)


∠ACD = 76°


Now,


∠ACD + ∠ECD= 180°


x = 180- 76°


x = 104°

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