Q12 of 76 Page 11

In Fig. 10.135, the measure of ∠B’AC’ is

In ABC and A'B'C',

AB= A'B' (Given)


∠B = ∠B'(Given)


BC = B'C' (Given)


Hence, by S.A.S. theorem,


ABC A'B'C'


Therefore,


By c.p.c.t


∠A = ∠A'


3x = 2x +20


x = 20°


Therefore angle A' = 2x +20


= 60°

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