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10. Congruent Triangles
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Q14 of 76 Page 11

In Fig. 10.136, AB ⊥ BE and FE ⊥ BE. If BC=DE and AB=EF, then Δ ABD is congruent to

In ABD and FEC,

AB= FE (Given)


∠B = ∠E (Each 90°)


BC = DE (Given)


Add CD both sides, we get


BD = EC


Therefore, by S.A.S. theorem,


ABD FEC

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10. Congruent Triangles
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