In Fig. 10.134, if AB = AC and ∠B = ∠C. Prove that BQ = CP.

Given,
∠B = ∠C
AB = AC
To Prove: BQ = CP
Proof: In
ABQ and
ACP
∠B = ∠C (Given)
AB = AC (Given)
∠A = ∠A (Common)
Hence, by A.S.A. Theorem
ABQ
ACP
BQ = CP (By c.p.c.t)
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