ABC is an isosceles triangle in which AB = AC. BE and CF are its two medians. Show that BE=CF.

Given,
ABC is an isosceles triangle
AB = AC
BE and CF are two medians
To prove: BE = CF
Proof: In ![]()
CE = BF (Since, AC = AB =
=
AB = CE = BF)
∠ECB = ∠FBC (Angle opposite to equal sides are equal)
BC = BC (Common)
Therefore, By SAS theorem
BEC ![]()
(By c.p.c.t)
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