Q5 of 76 Page 11

ABCD is a square, X and Y are points on sides AD and BC respectively such that AY = BX. Prove that BY = AX and BAY = ABX.


Given that ABCD is a square, X and Y are points on the sides AD and BC respectively.


Such that,


AY = BX


We have to prove: BY = AX and BAY = ABX


Join B and X, A and Y


Since, ABCD is a square


DAB = CBA = 90o


XAB = YBA = 90o (i)


Now, consider


We have,


XAB = YBA = 90o [From (i)]


BX = AY (Given)


AB = BA (Common side)


So, by RHS congruence rule, we have



(By c.p.c.t)



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Which of the following statements are true (T) and which are false (F):

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Fill in the blanks in the following so that each of the following statements is true.

(i) Sides opposite to equal angles of a triangle are ………


(i) Sides opposite to equal angles of a triangle are …………..


(iii) In an equilateral triangle all angles are ……….


(iv) In a Δ ABC, if A=C, then AB = ………


(v) If altitudes CE and BF of a triangle ABC are equal, then, AB = ……..


(vi) In an isosceles triangle ABC with AB=AC, if BD and CE are its altitudes, then BD is ….CE.


(vii) In right triangles ABC and DEF, if hypotenuse AB=EF and side AC=DE, then Δ ABC Δ …….