If the 10th term of an A.P. is 52 and 17th term is 20 more than the 13th term, find the A.P.
As we know, nth term in A.P. is a + (n-1)d
Where, a is first term
n is Nth term
d is difference between terms
Given 10th term of A.P. is 52
⇒ a+(10-1)d=52
And 17th term is 20 more than 13th term
⇒a+(17-1)d=a+(13-1)d+20
⇒12d+20=16d
⇒20=4d
⇒d=5
Also a + (10-1) d = 52
a + 9(5) = 52
⇒a=7
Conclusion: Therefore A.P. is 7+(n-1)5
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