Q30 of 47 Page 1

From the top of a tower, 100 m high a man observes two cars on the opposite sides of the tower and in same straight line with its base, with angle of depression 30° and 45°. Find the distance between the cars. [Take √3 = 1.732]


Given height of tower AC (h) = 100m


Let, x = BC


y = CD


In


Given


So,





In


Given


So,




Distance between cars = BC+CD = x + y = 173.2 + 100


= 273.2 m


Conclusion: Therefore, distance between cars is 273.2 m


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