The dimensions of a solid iron cuboid are 4.4 m 2.6 m 1.0 m. It is melted and recast into a hollow cylindrical pipe of 30 cm inner radius and thickness 5 cm. Find the length of the pipe.

For Cuboid,

Length, l = 4.4 m

Breadth, b = 2.6 m

Height, h = 1 m

As we know,

Volume of cuboid = lbh

Where l, b and h are length, breadth and height of cuboid respectively.

⇒ Volume of given cuboid, V = 4.4(2.6)(1) = 11.44 m³

For cylindrical pipe that is recast from hemisphere,

Base radius, r = 30 cm = 0.3 m [As, 1 m = 100 cm]

Let the length of pipe(or height) = h

We know that,

Volume of cylinder = πr²h

Where, r is base radius and h is the height of the cone.

Now,

⇒ Volume of cone = π(0.3)²h= 0.09πh

As the volume remains same, when a body is reformed to another body

Volume of cuboid = Volume of pipe

⇒ 11.44 = 0.09πh

⇒