Q3 of 47 Page 1

If a tower 30 m high, casts a shadow 10 m long on the ground, then what is the angle of elevation of the sun?



Let AB be a tower and BC be the shadow of tower,


Such that, AB = 30 m


BC = 10√3 m


⇒ Angle of elevation of sun = ∠ACB = θ


In ΔABC




⇒ θ = 60° [As tan 60° = √3]


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