Q21 of 47 Page 1

Solve for x:


Taking L.C.M





⇒ (8x + 4)(x + 4) = 25x2 + 30x + 5


⇒ 8x2 + 32x + 4x + 16 = 25x2 + 30x + 5


⇒ 17x2 - 6x - 11 = 0


⇒ 17x2 - 17x + 11x - 11 = 0


⇒ 17x(x - 1) + 11(x - 1) = 0


⇒ (17x + 11)(x - 1) = 0


⇒ 17x + 11 = 0 or x - 1 =0


⇒ or x = 1


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