Q6 of 26 Page 1

Write the structures of the following:

(i) H2S2O7


(ii) XeO3


(i) H2S2O7


Sulphur is the central atom with an oxidation state of +6. As the geometry of sulphate molecule has 4 oxygen atoms, the given molecule should have an oxygen to oxygen bond in order to have odd number of oxygen atoms implying a peroxide compound. Thus the structure can be given as:



(ii) XeO3


Xe is the central atom and has a oxidation state of +6. The 3 oxygen atoms are bonded by double bonds with Xe.



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