Q12 of 26 Page 1

The rate constant of a first order reaction increases from when the temperature changes from 300 K to 320 K. Calculate the energy of activation (Ea).

(log 2 = 0.301, log 3 = 0.4771, log 4 = 0.6021)


Given:


, ,


,


To find: activation energy (Ea)


Formula:


By substituting the given values, and applying the property of log(a/b)=log(a) – log(b) and log(a)x = xlog(a)




Solving the above equation gives



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