Q15 of 26 Page 1

When 1.5 g of a non-volatile solute was dissolved in 90 g of benzene, the boiling point of benzene raised from 353.23 K to 353.93 K. Calculate the molar mass of the solute.

Given:


Mass of solute = W2 = 1.5 g


Mass of solvent = benzene = W1 = 90 g


Elevation in B.P = 353.93-353.23 = 0.6 K


Kb for benzene = 2.52 K kg mol-1


To find: molar mass of solute


Formula:


substituting the above value in the equation gives:




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