In a Young’s double slit experiment using mono-chromatic light, the fringe pattern shifts by a certain distance on the screen when a mica sheet of refractive index 1.6 and thickness 964 micron (1 micron = 10-6 m) is introduced in the path of one of the Interfering waves. The mica sheet is then removed and the distance between the screen and the slits is doubled. �t is found that the distance between the successive maxima now is the same as the observed fringe-shift upon the introduction of the mica sheet. Calculate the wavelength of the monochromatic light used in the experiment.
Given, refractive index of mica, ![]()
Thickness of mica, ![]()
Let D be the distance between the slits and the screen, “d” be the distance between two slits and
be the wavelength of light.
Now, the fringe width is given by ![]()
The path difference when the mica sheet is present is ![]()
Therefore, the number of fringe shifted, ![]()
And the shift in the fringes is given by the fringe width multiplied by the number of fringes shifted.
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And for the second case, the fringe width is,
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Here, there’s no shift present.
From the question,
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