A long narrow horizontal slit is placed 1 mm above a horizontal plane mirror. The interference between the light coming directly from the slit and that after reflection is seen on a screen 1.0 m away from the slit. Find the fringe-width if the light used has a wavelength of 700 nm.
The distance between the screen and the slit, ![]()
Wavelength of light, ![]()
Here, we assume that the second slit is actually the virtual image of real slit.
Therefore, separation between the slits ![]()
Therefore, fringe width is ![]()
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