(a) Write the products formed when CH3CHO reacts with the following reagents:
(i) HCN
(ii) H2N-OH
(iii) CH3CHOin the presence of dilute NaOH
(b) Give simple chemical tests to distinguish between the following pairs of compounds:
(i) Benzoic acid and Phenol
(ii) Propanal and Propanone
OR
(a) Account for the following:
(i) Cl-CH2COOH is stronger acid than CH3COOH
(ii) Carboxylic acids do not give reactions of carbonyl group.
(b) Write the chemical equations to illustrate the following name reactions:
(i) Rosenmund reduction
(ii) Cannizzaro’s reaction
(c) Out ofCH3CH2-CO-CH2CH3 and CH3CH2-CH2-CO-CH3, which gives iodoform test?
(a) (i) CH3CHO + HCN → CH3-CH(CN)-OH
(ii) CH3CHO + H2N-OH → CH3CH=N-OH
(iii)
(b) (i) Add neutral FeCl3 in both the solutions, phenol forms violet colour but benzoic acid does not.
(ii) Tollen’s reagent test: Add ammonical silver nitrate (Tollen’s reagent) in both the solutions. Propanal gives silver mirror whereas propanone does not.
OR
(a) (i) Chlorine acts as electron withdrawing group, so it helps in dispersing the negative charge on carboxylate ion after releasing of H+ ions and thus making it stable. So, Cl-CH2COOH is stronger acid than CH3COOH
(b) (i) Rosenmund reduction:
Or
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(ii) Cannizzaro’s Reaction:
(c) CH3CH2-CH2-CO-CH3 shows iodoform test because it has a terminal methyl ketone group.
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