Draw the structures of the following :

(i) XeO₃

(ii) H₂SO₄

(i) XeO₃ is a tetrahedral molecule with sp³ hybridisation. It has a trigonal pyramidal structure.

Note:

A trick to find out hybridisation.

Z = Number of valence electrons on central atom + (number of monovalent groups attached) - (charge with sign).

Then we need to find out

If =2, then hybridisation is sp

If =3, then hybridisation is sp²

If =4, then hybridisation is sp³ and so on.

For XeO₃, number of valence electrons on Xe is 8 (noble gas), 0 monovalent groups attached (as O is bivalent) and the molecule is electrically neutral.

So, Z =8 and If =4, so hybridisation is sp³.

(ii) Structure of H₂SO₄ is as shown:

H₂SO₄ shows tetrahedral geometry with sp³ hybridisation. We can check the hybridisation from the above mentioned trick if we put the valence electrons of S as 6 and monovalent atoms as 2 (2 –OH groups).