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Mathematics
15. Areas of Parallelograms
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Q3 of 77 Page 15

Compute the area of trapezium PQRS in Fig. 15.76.

We have,

Area of trapezium PQRS = Area of rectangle PSRT + Area (Δ QRT)


Area of trapezium PQRS = PT * RT + (QT * RT)


= 8 * RT + (8 * RT)


= 12 * RT


In Δ QRT, we have


QR2 = QT2 + RT2


RT2 = QR2 - QT2


RT2 = (17)2 - (8)2


= 225


= 15


Hence,


Area of trapezium PQRS = 12 * 15


= 180 cm2


More from this chapter

All 77 →
1

In Fig. 15.74, compute the aresa of quadrilateral ABCD.

2

In Fig. 15.75, PQRS is a square and T and U are respectively, the mid-points of PS and QR. Find the area of Δ OTS if PQ=8 cm

4

In Fig. 15.77, ∠AOB=90°, AC=BC, OA=12 cm and OC=6,5 cm. Find the area of Δ AOB.

5

In Fig. 15.78, ABCD is a trapezium in which AB=7 cm, AD=BC=5 cm, DC=x cm, and distance between AB and DC is 4 cm. Find the value of x and area of trapezium ABCD.

Questions · 77
15. Areas of Parallelograms
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