Q9 of 77 Page 16

ABCD is a parallelogram. P is the mid-point of AB. BD and CP intersect at Q such that CO:OP = 3:1. If Find the area of parallelogram ABCD.

Given that,

CQ: QP = 3: 1


Let,


CQ = 3x


PQ = x


Area ( = 10 cm2


We know that,


Area of triangle = * Base * Height


Area ( = * x * h


10 = * x * h


x * h = 20


Area ( = * 3x * h


= * 3 * 20


= 30 cm2


Now,


Area ( = * PB * H = 30 cm2


PB * H = 60 cm2


We have to find area of parallelogram


We know that,


Area of parallelogram = Base * Height


Area ( = AB * H


Area ( = 2 BP * H


Area (ABCD) = 2 (60)


Area (ABCD) = 120 cm2


Hence,


Area of parallelogram ABCD is 120 cm2


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