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15. Areas of Parallelograms
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Q5 of 77 Page 16

PQRS is a rectangle inscribed in a quadrant of a circle of radius 13 cm. A is any point on PQ. If PS = 5 cm, then find

Given that,

PQRS is a rectangle


PS = 5 cm


PR = 13 cm


In triangle PSR, by using Pythagoras theorem


SR2 = PR2 – PS2


SR2 = (13)2 – (5)2


SR2 = 169 – 25


SR2 = 114


SR = 12 cm


We have to find the area ,


Area ( = * Base * Height


= * SR * PS


= * 12 * 5


= 30 cm2


Hence, Area ( is 30 cm2


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3

In Fig. 15.104, find the area of ΔGEF.


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In Fig. 15.105, ABCD is a rectangle with sides AB = 10 cm and AD = 5 cm. Find the area of ΔEFG.

6

In square AB2CD, P and Q are mid-point of AB and CD respectively. If AB = 8 cm and PQ and BD intersect at O, then find area of ΔOPB.

7

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Questions · 77
15. Areas of Parallelograms
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