Q16 of 77 Page 16

In a parallelogram ABCD, if ∠DAB=75° and ∠DBC=60°, then ∠BDC=

We know that,

The opposite angles of a parallelogram are equal

Therefore,

∠BCD = ∠BAD = 75°

Now, in ∆ BCD, we have

∠CDB + ∠DBC + ∠BCD = 180° (Since, sum of the angles of a triangle is 180o)

∠CDB + 60° + 75° = 180°

∠CDB + 135° = 180°

∠CDB = (180° - 135°) = 45°

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