In square AB2CD, P and Q are mid-point of AB and CD respectively. If AB = 8 cm and PQ and BD intersect at O, then find area of ΔOPB.
Given: ABCD is a square
P and Q are the mid points of AB and CD respectively.
AB = 8cm
PQ and BD intersect at O
Now,
AP = BP =
AB
AP = BP =
* 8
= 4 cm
AB = AD = 8 cm
QP ‖ AD
Then,
AD = QP
So,
OP =
AD
OP =
* 8
= 4 cm
Now,
Area (
=
* BP * PO
=
* 4 * 4
= 8 cm2
Hence, Area (
is 8 cm2
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