Q4 of 97 Page 790

The parallel sides of a trapezium are 9.7 cm and 6.3 cm, and the distance between them is 6.5 cm. The area of the trapezium is

Given:


Side 1 = 9.7 cm


Side 2 = 6.3 cm


Distance between sides = 6.5 cm



Area of trapezium = 1/2 × sum of parallel sides × distance between them


= 1/2 × (9.7 + 6.3) × 6.5


= 1/2 × 16 × 6.5


= 52 cm2

More from this chapter

All 97 →
2

In the given figure ABCD is a trapezium in which AB = 40 m. BC = 15 m, CD = 28 m, AD = 9 m and CE ⊥ AB. Area of trap. ABCD is

 3

The sides of a triangle are in the ratio 12 : 14 :25 and its perimeter is 25.5 cm. The largest side of the triangle is

 5

Find the area of an equilateral triangle having each side of length 10 cm. [Take √3 = 1.732.]

 6

Find the area of an isosceles triangle each of whose equal side is 13 cm and whose base is 24 cm.