Q10 of 97 Page 790

Find the area of a triangle whose sides are 42 cm, 34 cm and 20 cm.

Given: Side 1 = a (let) = 42 cm


Side 2 = b (let) = 34 cm


Side 3 = c (let) = 20 cm



We know that,


Area of a scalene triangle = √(s(s-a)(s-b)(s-c))


Where,




⇒ s = 48 cm


Now,


Area of a scalene triangle = √(48cm × (48-42)cm × (48-34)cm × (48-20)cm)


= √(48cm × 6cm × 14cm × 28cm)


= √112896 cm2


= 336 cm2


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