The edge length of a unit cell of a metal having molecular mass 75 g/mol is 5 A◦ which crystallizes in a cubic lattice. If the density is 2g/cc, then find the radius of the metal atom.
Given:
Molecular mass, M = 75g
Edge Length, a= 5 A° = 5 × 10-10 m
Density, d = 2g/cc
To find: Radius of the metal atom, r
Solution:
![]()
Where z = number of atoms present per unit cell
![]()
![]()
Z = 2
Since the number of atoms is 2, the metal crystallizes in BCC structure.
![]()
![]()
r = 2.165 A° = 216.5 pm
Therefore the radius of the metal atom is 216.5 pm.
Couldn't generate an explanation.
Generated by AI. May contain inaccuracies — always verify with your textbook.
