Write the correct formulae for the following coordination compounds:

(i) CrCl₃.6H₂O (violet with 3 chloride ions precipitated as AgCl)

(ii) CrCl₃.6H₂O (light green colour, with 2 chloride ions precipitated as AgCl)

(iii)CrCl₃.6H₂O (dark green colour, with 1 chloride ion precipitated as AgCl)

(i) Since three chloride ions are precipitated as AgCl, all the 6 molecules of water are present as ligand and chromium is the central metal. Therefore the formula of the compound is follows:

[Cr (H₂O) ₆]Cl₃

(ii) Since two chloride ions are precipitated as AgCl, all the 5 molecules of water and one chlorine atom is present as ligand and chromium is the central metal. Therefore the formula of the compound is follows:

[Cr (H₂O) ₅ Cl]Cl₂. (H₂O)

(iii) Since one chloride ions are precipitated as AgCl, all the 4 molecules of water and two chlorine atom is present as ligand and chromium is the central metal. Therefore the formula of the compound is follows:

[Cr (H₂O) ₄ Cl₂]Cl. (H₂O) ₂