A voltaic cell is set up at 25◦C with the following half cell;
Al / Al3+ (0.001 M) and Ni /Ni2+ (0.50 M)
Calculate the cell voltage. [ E◦ Ni2+/Ni = - 0.25V, E◦Al3+/Al = -1.66V]
Given:
E◦ Ni2+/Ni = - 0.25V
E◦Al3+/Al = -1.66V
Concentration of [Ni+2] = 0.50 M
Concentration of [Al+3] = 0.001 M
Using Nernst’s Equation:

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= -0.25 – (0.02955× 0.30103)
= -0.25 – 0.0089
= -0.2589V

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= -1.66 – (0.0197× 3)
= -1.66 – 0.0591
= -1.7191 V
Ecell = -0.259 – (-1.7191)
= -0.259 + 1.7191
= 1.46 V
Therefore the cell voltage is 1.46 V.
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