Q4 of 34 Page 1

In the given figure PA and PB are tangents to a circle with centre O. If APB = (2x3 and AOB = (3x7, then find the value of x)


Now, here, APBO is a quadrilateral where, OAP = 90°& OBP = 90°


Also, the sum of the angles of the quadrilateral is 360°.


Hence, the sum of opposite angles is 180°.


AOB + ∠∠APB = 180°


3x + 7 + 2x + 3 = 180°


5x + 10 = 180


5x = 170


x = 34°


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