In the given figure PA and PB are tangents to a circle with centre O. If ∠APB = (2x3 and ∠AOB = (3x7, then find the value of x)


Now, here, APBO is a quadrilateral where, ∠OAP = 90°& ∠ OBP = 90°
Also, the sum of the angles of the quadrilateral is 360°.
Hence, the sum of opposite angles is 180°.
⇒ ∠AOB + ∠∠APB = 180°
⇒ 3x + 7 + 2x + 3 = 180°
⇒ 5x + 10 = 180
⇒ 5x = 170
⇒ x = 34°
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