Cards marked with numbers 1, 3, 5… 49 are placed in a box and mixed thoroughly. One card is drawn from the box. Find the probability that the number on the card is
Multiple of 3 and 5.
As the numbers of cards in an AP, with first term a = 1 and common difference d = 2
Let the no of cards be 'n'
Number on nth card = 49
⇒ a + (n - 1)d = 49 [As nth term of an AP = a + (n - 1)d ]
⇒ 1 + (n - 1)2 = 49
⇒ (n - 1)2 = 48
⇒ n - 1 = 24
⇒ n = 25
Total No of cards = 25
Cards having no's multiple of 3 and 5 = {15, 30, 45}
No of cards having no's multiple of 3 and 5 = 3
We know that,
Probability of an event 
⇒ Probability of getting a card having a number multiple of 3 and 5
Couldn't generate an explanation.
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