From a point 100 m above a lake the angle of elevation of a stationary helicopter is 30° and the angle of depression of reflection of the helicopter in the lake is 60ᵒ. Find the height of the helicopter above the lake.

Let A be the point 100 m above lake and C be the helicopter and C' be the reflection of helicopter in water.
Given,
Angle of elevation of helicopter from point A, ∠CAQ = 30° [Let θ1]
Angle of depression of reflection from point A, ∠QAC' = 60° [Let θ2]
Also,
AB = PQ = 100 m …[1]
AQ = BP …[2]
CP = CP' [image distance is equal to object distance]
And let CQ = 'x'
∴CP = CQ + PQ = 100 + x
⇒ CP' = 100 + x …[3]
In ΔACQ
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From [2]
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⇒ BP = x√3 m …[4]
In ΔAQC'
![]()
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[From [3]]
⇒ 3x = x + 200
⇒ 2x = 200
⇒ x = 100 m
And
Height of helicopter above lake = CP = x + 100
= 100 + 100 = 200 m
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