Q7 of 34 Page 1

Find the value(s) of, for which the equation kx2 – kx + 1 = 0 has equal roots.

We know that, A quadratic equation ax2 + bx + c = 0 has equal roots if and only if D = 0


Where,


D(Discriminant) = b2 - 4ac


In the given equation,


a = k


b = -k


c = 1


Putting values, we get


D = (-k)2- 4(k)(1)


⇒ 0 = k2 - 4k


⇒ k2 = 4k


⇒ k = 4


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