Cards marked with numbers 1, 3, 5… 49 are placed in a box and mixed thoroughly. One card is drawn from the box. Find the probability that the number on the card is
divisible by 3
As the numbers of cards in an AP, with first term a = 1 and common difference d = 2
Let the no of cards be 'n'
Number on nth card = 49
⇒ a + (n - 1)d = 49 [As nth term of an AP = a + (n - 1)d ]
⇒ 1 + (n - 1)2 = 49
⇒ (n - 1)2 = 48
⇒ n - 1 = 24
⇒ n = 25
Total No of cards = 25
Cards having no's divisible by 3 = {3, 9, 15, 21, 27, 33, 39, 45}
No of cards having no's divisible by 3 = 8
We know that,
Probability of an event ![]()
⇒ Probability of getting a card having a number divisible by 3
![]()
![]()
Couldn't generate an explanation.
Generated by AI. May contain inaccuracies — always verify with your textbook.