The value of (3x3 +9x2 + 27x) ÷ 3x is
(a) x2 +9 + 27x (b) 3x3 +3x2 + 27x
(c) 3x3 +9x2 + 9 (d) x2 +3x + 9
(d)
Given: (3x3 +9x2 + 27x) ÷ 3x
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= x2 + 3x + 9
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