State whether the statements are true (T) or false (F).
Common factor of 12a2b2+4ab2-32 is 4.
Let us consider that common factor of 12a2b2 + 4ab2 – 32 = 4
Check: 12a2b2 + 4ab2 – 32 = 4 (3a2b2 + ab2 – 8)
Notice, there are no further common factor in the equation.
Thus, common factor of 12a2b2 + 4ab2 – 32 is 4.
Hence, the statement is true.
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