Q4 of 59 Page 254

Find the product of the following monomials

−3a, 4ab, −6c, d

Here we have -3a,4ab,-6c,d

Hence the product of the above terms is (-3a)×(4ab)×(-6c)×(d)


= (-3×4×-6)(a.a)(b)(c)(d)


= 72a2bcd


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