Subtract the product of 2x(5x−y) from product of 3x(x + 2y)

Here we have 2x(5x-y) and 3x(x + 2y)

Using the distributive law 2x(5x-y) = 2x(5x)-2x(y)

= 10x²-2xy

and 3x(x + 2y)

= 3x(x) + 3x(2y)

= 3x² + 6xy.

Now , we have to subtract 10x²-2xy from 3x² + 6xy.

i.e. (3x² + 6xy)-(10x²-2xy)

= 3x² + 6xy-10x² + 2xy

= -7x² + 8xy

Hence after subtraction of the product of 2x(5x−y) from the product of 3x(x + 2y) is

-7x² + 8xy.