Q4 of 59 Page 256

Add the product: a(a−b), b(b−c), c(c−a)

Here we have the expressions a(a-b),b(b-c) and c(c-a)

Using the distributive law a(a-b) = a2-ab,b(b-c) = b2-bc and c(c-a) = c2-ca


Now we add the terms (a2-ab) + (b2-bc) + (c2-ca)


= a2 + b2 + c2-ab-bc-ca


Hence addition of the product of the above expressions is a2 + b2 + c2-ab-bc-ca.


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