Find the product:

(a−2b + 3c)(ab²−a²b)

Consider the trinomial a−2b + 3c and the binomial ab²−a²b.

Now, to get the product of a−2b + 3c and ab²−a²b,we use the

distributive law i.e. (a−2b + 3c)×( ab²−a²b) = a(ab²-a²b)-2b(ab²-a²b) + 3c(ab²-a²b)

= a²b²-a³b-2ab³ + 2a²b² + 3ab²c-3a²bc = 3a²b²-a³b-2ab³ + 3ab²c-3a²bc

Therefore , the product of a−2b + 3c and ab²−a²b is 3a²b²-a³b-2ab³ + 3ab²c-3a²bc