Simplify x(2x²−7x + 3) and find the values of it for (i) x = 1 and (ii) x = 0

Here we have the monomial x and polynomial 2x²-7x + 3

Now the product of these terms is as follows:

The process involved in the multiplication is :

Step1.Write the product of the expressions using multiplication symbol:

x(2x²-7x + 3).

Step2.Use distributive law :Multiply the monomial by the first term of the trinomial then multiply the monomial by the second term of the trinomial and then the monomial by the third term of the trinomial and then add their products: x(2x²)-x(7x) + x(3)

Step3.Simplify the terms: 2x³-7x² + 3x

Hence x(2x²−7x + 3) = 2x³-7x² + 3x

(i)When x = 1, 2x³-7x² + 3x = 2(1)³-7(1)² + 3(1) = -2

(ii)When x = 0, 2x³-7x² + 3x = 2(0)³-7(0)² + 3(0) = 0