Simplify the following:

(m + n)(m²−mn + n²)

We have the binomial m + n and trinomial m²−mn + n²

Here we will use the distributive law as follows:

(m + n)(m²−mn + n²) = m(m²−mn + n²) + n(m²−mn + n²) = (m.m²-m.mn + m.n²) + (n.m²-mn.n + n.n²) = m³-m²n + mn² + m²n-mn² + n³ = m³ + n³

Hence , (m + n)(m²−mn + n²) = m³ + n³