Q2 of 59 Page 258

Find the product:

(p3 + q3)(p−5q + 6r)

Consider the binomial p3 + q3 and the trinomial p−5q + 6r.

Now, to get the product of p3 + q3 and p−5q + 6r,we use the


distributive law i.e (p3 + q3)(p−5q + 6r) = p3(p-5q + 6r) + q3(p-5q + 6r) = (p3.p-5p3q + p3.6r) + (p.q3-5q.q3 + 6q3r) = p4-5p3q + 6p3r + pq3-5q4 + 6q3r


Therefore , the product of p3 + q3and p−5q + 6r is p4-5p3q + 6p3r + pq3-5q4 + 6q3r


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