Q5 of 64 Page 77

Three metallic cubes of side 3 cm, 4 cm and 5 cm respectively are melted and are recast into a single cube. Find the total surface area of the new cube.

Given:

three cubes of side 3 cm, 4 cm and 5cm


Total volume of all cube = volume of new cube


(3)3 + (4)3 + (5)3 = (a)3


27 + 64 + 125 = (a)3


216 = (a)3


a = 6


TSA of cube = 6a2


= 6(6)2


TSA of cube = 216cm2


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