Three metallic cubes of side 3 cm, 4 cm and 5 cm respectively are melted and are recast into a single cube. Find the total surface area of the new cube.
Given:
three cubes of side 3 cm, 4 cm and 5cm
Total volume of all cube = volume of new cube
(3)3 + (4)3 + (5)3 = (a)3
27 + 64 + 125 = (a)3
216 = (a)3
⇒ a = 6
TSA of cube = 6a2
= 6(6)2
⇒ TSA of cube = 216cm2
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