Mohan wanted to paint the walls and ceiling of a hall. The dimensions of the hall is 20m x15m x6m. Find the area of surface to be painted and the cost of painting it at ₹78 per sq. m.
Given:
l = 20m, b = 15m and h = 6m
area of walls and ceiling to be renovated = 2(lh + bh) + lb)
= 2(20(6) + 15(6)) + 20(15)
= 2(120 + 90 )+ 300
= 2(210) + 300
= 420 + 300 = 720 m2
⇒ area = 720m2
Cost of 1m = Rs 78
Cost of 720 m2 = 720× 48
= Rs 56160
Couldn't generate an explanation.
Generated by AI. May contain inaccuracies — always verify with your textbook.