Write True/False in the following and give the reason of your answer if possible.
(i) AB and CD are chords of measure 3 cm and 4 cm respectively of a circle by which the angles subtended at the centre are respectively 70° and 50°.
(ii) Chords of a circle whose lengths are 10 cm and 8 cm are initiated at distances 8 cm and 5 cm respectively from the centre.
(iii) Out of the two chords AB and CD of a circle each is at a distance of 4 cm from the centre. Then AB = CD.
(iv) Congruent circles with centres O and O’ intersect at two points A and B. Then ∠AOB = ∠AO’B.
(v) A circle can be drawn through three collinear points.
(vi) A circle of radius 4 cm can be drawn through two points A and B of AB = 8 cm.
(i) False
We know that longer chords subtend at greater angles and smaller chords at smaller angles.
Here CD (longer chord) is subtending at 50° (smaller angle) while AB (smaller chord) is subtending at 70° (greater angle).
So, it is false.
(ii) False
We know that longer the chord, smaller the distance from centre.
Here, 10 cm chord is at a distance of 8 cm from the center, hence it is not possible that 8 cm chord is at a distance of 5 cm from the center.
(iii) True
We know that if two chords are at equal distance from the centre, they are equal.
Here, chords AB and CD are at equal distance of 4 cm from the centre.
∴ AB = CD
Hence, it is true.
(iv) True

We know that equal chords of congruent circles subtend equal angles at the corresponding centres.
If we take AB as chord, and as radius of both circle are equal
⇒ ∠AOB = ∠AO’B
So, it is true.
(v) False
A circle passing through two collinear points cannot pass through the third point.
Hence, it is false.
(vi) True
Given radius = 4 cm
We know that diameter is twice the radius.
When a circle is drawn through two points A and B, diameter will be AB = 8 cm.
Taking a compass, from the centre O and OA or OB as radius, we join A to B and B to A.
So, the circle can be drawn through A and B.
∴ It is true.
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