Q11 of 63 Page 156

AD is a diameter of a circle and AB is a chord. If AD = 34 cm, AB = 30 cm, then the distance of AB from the centre of the circle is—

We know that Length of chord,


Where r = radius of circle, d = distance of chord from centre


Given diameter AD = 34 cm and chord AB = 30 cm


⇒ Radius = 34/ 2 = 17 cm


Now,


⇒


⇒


Squaring on both sides,


⇒


⇒ 900 = 4 (289 – d2)


⇒900/ 4 = 289 – d2


⇒225 = 289 – d2


⇒ d2 = 289 – 225


⇒ d2 = 64


∴ Distance of chord, d = 8 cm

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