If a diameter of a circle bisects each of the two chords then the chords will be—

AB and CD are two chords.
Let EF be the diameter of the circle.
We know that if a radius bisects a chord, then it is perpendicular to the chord.
⇒ EF ⊥ CD and EF ⊥ AB
∴ AB || CD
∴ If a diameter bisects each of the chords, then the chords will be parallel.
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