Q13 of 63 Page 156

If AB = 12 cm, BC = 16 cm, and AB is perpendicular to line segment BC then the radius of the circle passing through A, B and C is—

We know that Length of chord,


Where r = radius of circle, d = distance of chord from centre


Given AB = 12 cm and BC = 16 cm


Now,


⇒


⇒


Squaring on both sides,


⇒


⇒ 256 = 4 (r2 – 144)


⇒ 256/ 4 = r2 – 144


⇒ 64 = r2 – 144


⇒ d2 = 289 – 225


⇒ d2 = 64


∴ Distance of chord, d = 8 cm

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